<{p}>下面的程序是用do while语句求1至1000之间满足“用3除余2；用5除余3；用7除余2”的数，且一行只打印五个数。<{br/}>int i=1,j=0;<{br/}>do{<{br/}> if(【1】)<{br/}> {printf("%4d",i);<{br/}> j=j+1;<{br/}> if(【2】) printf(" ");}<{br/}> i=i+1;<{br/}>}while(i<1000);<{br/}><{/p}>