【多选题】
A SELECT TO_CHAR(TO_DATE ('29-10-2019') + INTERVAL '2' MONTH + INTERVAL '5' DAY - INTERVAL
'86410' SECOND, 'DD-MON-YYYY') AS "date"
FROM DUAL;
B SELECT TO_CHAR(TO_DATE('29-10-2019') + INTERVAL '3' MONTH + INTERVAL '7' DAY - INTERVAL
'360' SECOND, 'DD-MON-YYYY') AS "date"
FROM DUAL;
C SELECT TO_CHAR(TO_DATE('29-10-2019') + INTERVAL '2' MONTH + INTERVAL '5' DAY - INTERVAL
'120' SECOND, 'DD-MON-YYYY') AS "date" FROM DUAL;
D SELECT TO_CHAR(TO_DATE('29-10-2019') + INTERVAL '2' MONTH + INTERVAL '6' DAY - INTERVAL
'120' SECOND, 'DD- -MON-YYYY') AS "date"
FROM DUAL;
E SELECT TO_CHAR(TO_DATE ('29-10-2019') + INTERVAL '2' MONTH + INTERVAL '4' DAY - INTERVAL
'120' SECOND, 'DD-MON-YYYY') AS "date"
FROM DUAL;
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